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0.36+0.12y=-1.15y^2
We move all terms to the left:
0.36+0.12y-(-1.15y^2)=0
We get rid of parentheses
1.15y^2+0.12y+0.36=0
a = 1.15; b = 0.12; c = +0.36;
Δ = b2-4ac
Δ = 0.122-4·1.15·0.36
Δ = -1.6416
Delta is less than zero, so there is no solution for the equation
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